Freshman Christina Keesey Named Big Ten Women’s Tennis Player of the Week – Ohio State Buckeyes
3/21/2007 12:00:00 AM | Women's Tennis
March 21, 2007
COLUMBUS, Ohio – Ohio State freshman Christina Keesey has been named the Big Ten Women’s Tennis Player of the Week, the conference announced Wednesday. Keesey posted two singles wins for the Buckeyes Monday, as the team downed No. 16 Wichita State (4-3) and Florida Gulf Coast (7-0) in Fort Myers, Fla.
Keesey, from Northfield, Minn., (Northfield High School) was 2-0 for the Buckeyes at No. 3 singles. Against No. 16-ranked Wichita State, Keesey clinched the Buckeyes’ upset victory, coming back from a set down to beat Lenore Lazaroiu, 5-7, 6-3, 7-5. The match was tied at 3-all when Keesey posted the win, leading the Buckeyes to their first win over a Top 16 opponent since downing No. 16-ranked William and Mary Feb. 29, 2004. Keesey closed out the day with a straight-set, 6-1, 6-1, victory over Krista Polulak of No. 11-ranked (Division II) Florida Gulf Coast.
Keesey, who is on a six-match winning streak, has a Buckeye-best 18 overall wins this season and is first with 11 dual-match victories.
Keesey is the first Buckeye to be honored by the league this season and the first since Lindsay Williams in February 2004.
The Buckeyes return to Big Ten action with two matches this weekend. The team will play at Minnesota at 7:30 p.m. ET Friday in Minneapolis and at Iowa at noon ET Sunday in Iowa City.
