April 22, 2002

COLUMBUS, Ohio – Leftfielder Mike Rabin (Fr., West Chester, Ohio/Lakota East) was named the Big Ten Player of the Week Monday after helping the Buckeyes win two of three games at Indiana by hitting .667 (6-for-9) in the series.

Rabin also produced four RBIs and three runs as the Buckeyes maintained their position atop the league and extended their lead to two games in the loss column over three teams. For the week, Rabin batted a sizzling .727 (8-11) with four runs batted in, four runs, four walks, two stolen bases and an on-base percentage of .800. In the process, he climbed to second in the league with a .447 batting average in conference games only, trailing only Minnesota’s Luke Appert (.462).

In his last 10 games, he is batting .412 (14-for-34). Rabin is now batting .352 on the season, which is third best on the team. He has started the last eight games in left field and is batting .480 in those starts after batting only .283 up to that point of the season. Rabin has started a total of 19 games, but in 14 starts in left, he is batting .419.

Rabin is the second Buckeye in the past three weeks to earn Big Ten Player of the Week honors, as teammate Christian Snavely was selected on April 8.

Ohio State plays host to the College of Wooster at 6:35 p.m. on Wednesday at Bill Davis Stadium. The Buckeyes will then play host Purdue in a four-game series this weekend beginning at 6:35 p.m. on Friday.