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April 24, 2006

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COLUMBUS, Ohio – The No. 7 Ohio State men’s tennis team heads to Minneapolis, Minn., this weekend to begin play in the 2006 Big Ten Tournament. The Buckeyes enter postseason conference tournament play as the No. 1 seed, a first in program history.

Ohio State is 22-1 overall and 10-0 in league play. The Buckeyes will open the conference tournament at 11 a.m. (EDT) Friday against the winner of the (No. 8 seed) Wisconsin vs. (No. 9) Purdue match Thursday. Ohio State’s league title this year is the fifth in program history (1912-present), the last was the 2001 Big Ten Conference Tournament title.

Ohio State clinched the outright regular season Big Ten title Sunday by defeating Wisconsin 6-1. OSU capped a perfect conference regular season by going 10-0.

Wisconsin finished the 2005-06 regular season 10-11 overall and 3-7 in the Big Ten. Ohio State is riding a nine-match win streak against the Badgers. The last Wisconsin win against OSU came during the 1998-99 season in Madison by a score of 6-1.

Purdue is 8-14 on the year and 3-7 in the Big Ten. Ohio State holds the edge over Purdue with a 64-18 record that includes a seven-match win streak dating back to 1998-99. The last Boilermaker win over the Buckeyes (4-3) was during the 1998-99 season.

The Ohio State opener is scheduled for 11 a.m. EDT Friday at the Baseline Tennis Center in Minneapolis, Minn. The University of Minnesota will be hosting the event. Updated brackets and results can be found at gophersports.com throughout the event.