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COLUMBUS, Ohio – For the fifth-consecutive season, the No. 4 Ohio State men’s tennis team will play host to the First and Second Rounds of the NCAA Division I Championships it was announced Tuesday. Among the field of 64, the Buckeyes earned the fourth-seed and will welcome Michigan, Denver and Western Michigan to Stickney Tennis Center May 15-16.

Ohio State (32-1), the 2009 NCAA Championship runner-up, will play Western Michigan (21-10) in the first round at 1 p.m. May 15. The first match of the day between the Wolverines and Pioneers will begin at 10 a.m. The winners of the opening-round matches will play at noon May 16.

The Buckeyes are 5-0 all time against the Broncos, with Ohio State winning the last meeting, 4-3, in Columbus during the 1998-99 season.

The 16 remaining teams after the second round will travel to Athens, Ga., for the remainder of the championship May 21-25 at the Dan Magill Tennis Complex.

Ohio State owns a 22-10 all-time record in the NCAA team championship. Among the contingent traveling to Columbus next weekend, Ohio State has only faced Michigan in the NCAA championship. The Buckeyes downed the Wolverines, 4-1, in the second round last year at Stickney Tennis Center. 

After winning its fifth-consecutive Big Ten Tournament title May 2 in Bloomington, Ind., Ohio State earned an automatic bid into the championship. The Buckeyes also have won the conference regular-season title five straight times.